Nº23 Michael Pasman

Win

Section B.1.

Michael Pasman (Israel)

wKd7,Nb5,h1,Pb2/bKb6,Pa4,c6,f3

1.Na3! The point iis that it is impossible to avoid exchange of b2 pawn. So white has to prepare himself to Black king penetraton to direction of b2 pawn in best way. And as you will see later there is some important detail to achieve when the pawn is exchanged. So the knight goes to some unpredicted square. He could do it also through d4 – which is more natural square, but ..
Try : 1.Nd4? c5! 2.Nxf3 (Here 2.Nc2 is not good enough 2…Kb5 3.Kd6 Kc4 4.Na3+ Kb3 5.Kxc5 Kxb2 6.Kb4 Kc1 7.Kc3 Kd1) 2…Kb5 3.Nf2! (3.Nd2 a3 4.bxa3 c4=) 3…a3! 4.bxa3 Ka4! 5.Nd2 Kxa3! 6.Nd3 c4!=; Other moves can not avoid it too
1.Nc3? Ka5! 2.Na2 (2.Kxc6 Kb4=; 2.Kd6 Kb4 3.Nd1 c5 4.Kd5 c4 5.Nhf2 a3 6.bxa3+ Kxa3=) 2…c5 3.Ke6 (3.Kd6 c4 4.Kc5 a3 5.bxa3 Ka4 6.Nf2 Kxa3=) 3…c4 4.Kd5 a3 5.bxa3 Ka4 6.Nc3+ Kxa3= draw – because black c pawn was stopped too far – on 4-th rank. It has to be stopped with knight on 5-rank or with the king on 6-rank – because afterwards it must be change to knight on 5-th Rank

1…Kc5!
1…c5 2.Kd6+-

2.Nc2!
2.Nf2? Kb4 3.Kxc6 (3.Kd6 Kb3 4.Kc5 Kxb2 5.Kb4 c5+! 6.Kxa4=) 3…Kb3 4.Kb5 (4.Nb5 Kxb2) 4…Kxb2=
2.Kc7? Kb4 3.Kd6 Kb3 4.Kc5 Kxb2 5.Kb4 c5+=
2.Nb1? Kc4 3.Nd2+ Kd3=

2…Kc4!
2…Kd5!? 3.Kc7! a) 3.Na3!+- Kc5!; b) c5 Kc7 3.Ne3+- Kc5 Kd4 4.Kxc6 4.Nf2 Kb4 5.Kd6+- Kb3 c5 6.Kd5 6.Kc5 (6.Ned1 c5 7.Kxc5 a3 8.bxa3 Kxa3=) 6…Kxb2 7.Kb4 c5+ 8.Kxa4=; 3…Kc4 4.Na1 Kd3 5.Kd6 Kd2 6.Kc5 The same 6…Kc1 7.b4 axb3 8.Nxb3+- See main line

3.Na1!! ] Look at 2 White knights… Ideal defensive position …
3.Ne3+? Kb3 4.Nd1 Kc2 5.Nhf2 c5 6.Kc6 c4 7.Kc5 c3 8.Nxc3 Kxb2 9.Nxa4+ Draw

3…Kd3
3…c5 4.Kc6 Kb4 (4…Kd4 5.Kb5 Kd3 6.Kxc5 Kd2 7.Kb4) 5.Kd5 c4 6.Kd4+-
3…Kb5 4.Kd6+-
3…Kd5 4.Kc7+- c5 5.Kb6! c4 Kc4 Ka5 6.Kb5+-

4.Kd6!! Important to keep c6 pawn and to keep it as far as possible from promotion point
4.Kxc6? Kd2 5.Nf2 Kc1 6.b3 axb3 7.Nxb3+= White cannot win against f3 pawn – it is too far advanced

4…Kd2 5.Kc5!
5.Nf2? Kc1 6.b4 axb3 7.Nxb3+ Kb2= 8.Nd4 (8.Nc5 Kc3!=) 8…c5!!=
5.Ng3? f2 6.Kc5 Kc1 7.b4 axb3 8.Nxb3+ Kd1=

5…Kc1 6.b4!
6.b3? a3!=

6…axb3
6…Kb2 7.Kxc6 Kxa1 8.b5 a3 9.b6 a2 10.b7 Kb1 11.b8Q+-

7.Nxb3+ Kd1 8.Nd4! Ke1
8…f2 9.Nxf2+-

9.Nxf3+ Kf1 10.Nh4! Kg1 11.Ng3+- White, after placing the Knight in box c4, achieved the «Troiski position»