Nº9 Peter S. Krug

Win

Peter S. Krug (Austria)

wKg1,Nb4,Bf5,Rh7,Pa2,a5,b2/bKa8,Qd6,Ne5

1.Be4+! Kb8 2.Rh8+ Kc7 3.Nd5+ Kb7
3…Kc6 4.b4 Kb5 5.Rc8 Ka4 6.Rc3+-
3…Kd7 4.Nb6+ Ke6 5.Rh6+-

4.Rh7+!
4.b4? Nc6 5.a4 Qe5 6.a6+ Ka7 7.Rh7+ Kb8 8.Rb7+ Kc8 9.Nb6+ Kd8 10.Rd7+ Ke8 11.Bxc6 Qe3+=

4…Kb8
4…Kc6 5.a6! Qc5+ 6.Kg2 Qd4 7.Nc3+ Kc5 8.a7 Qd2+ 9.Kf1 Ng4 10.Rc7+ Kd6 11.Rc6+ Ke7 (11…Ke5 12.Rc5+ Kf6 (12…Kf4 13.Ne2+-) 13.Rf5+ Ke6 14.Nd5 Qc1+ 15.Kg2 Qxb2+ 16.Kg3 Qa3+ 17.Kxg4 Qxa7 18.Nf4+-) 12.Nd5+ Kf7 13.Rc7+ Ke6 14.Re7+ Kd6 15.Rf7 Nh2+ 16.Kg1 Qe1+ 17.Kxh2 Qh4+ 18.Kg1 Qe1+ 19.Rf1 Qg3+ 20.Bg2+-
4…Ka6 5.b4 Kb5 6.a6 Kxa6 (6…Ng4 7.Kg2 Qe5 8.Re7 Qh2+ 9.Kf3 Ne5+ 10.Rxe5 Qxe5 11.a7 Qh5+ 12.Ke3+-) 7.a4 Nd7 8.Kf2+-

5.a6 Qxa6 6.Rh8+
6…Kb7 7.Nb4+-

6…Ka7 7.Ra8+ Kxa8 8.Nc7/b4+ Ka7 9.Nxa6 Kxa6 10.Bg2!
10.Kf2? Ka5! 11.Ke2 Nc4! 12.b3 Nd6 13.Kd3 Kb4!÷

10…Ka5 11.Bf1 Nd7 12.Be2!
12.Kf2? Nb6! 13.Ke3 Na4!= (13…Kb4? 14.Kd2+-)

12…Kb4
12…Nb6 13.a3 Ka4 14.Bd1+-

13.Bd1 Ne5
13…Kc4 14.Kf2 /f1 14…Kd3 15.Ke1+-

14.a3+ Kb5 15.Kg2!
15.Kf1? Kc4 16.Ke2 Nd3 17.b3+ (17.Bb3+ Kd4=) 17…Kc3=

15…Kc4 reciprocal Zugzwang 16.Kf1 Nd3
16…Kd3 17.Ke1!+-

17.Be2+-