Pagina 3 – Correcciones

PARTE III – PDF-VER-DESCARGAR (TODOS – 147 Estudios)

EJEMPLOS

Ericsson A.- Springaren-1955-Ganan Correction

1.Af3,Rg6; 2.Ae4,Rf7; 3.Ad5,Dd5; 4.0-0,Re8; 5.Cf6+– 1.Cef6 cook ,Rg6; 2.Ae4,Rg7; 3.0-0+-

Solución:1.Af3+ [1.Cgf6+? Rg6 2.Ae4+ Rf7 3.0–0 Re7 4.Te1 Rd8 5.Td1+ Rc8 6.Cd5 Rb8 7.Ce7 Da1=] 1…Rg6 2.Ae4+ Rf7 3.Ad5+ Dxd5 4.0–0+ Rxe8 5.Cf6++-

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V. Evreinov -FIDE Revue- 1961.-Ganan Correction

Solución: 1.Af2,Ag2; 2.Ac4,Th6; 3.Ad3,Th5; 4.Ae2,Th4; 5.Tf7,Tb4; 6.Th7,Ah4; 7.Ad3,Tf4; 8.Af5,Tf5; 9.Th4++-En 2.Ad3 cook ,Tf8; 3.Tf8,Af8; 4.Af5++

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Fritz J.-Norodni Listy.-1931.-Tablas Corrected by S. Didukh

Solución: 1.c7,Ah7; 2.Re6,Cf7; 3.Cg3,Cg3; 4.c8=D,Af5; 5.Rd5,Ac8=En 2…,Ce3 cook; 3.Cg3,Ag8; 4.Rd7,Cd5/c4-+

Correction 06.2012 of Sergio Didukh 1.Rd7 Ah7 2.Re6 Cf7 3.Cg3! Cxg3 4.c8D Af5+ 5.Rxd5 Ae4+ 6.Re6 Af5+ 7.Rd5 Axc8 model stalemate

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Filaretov S. P- Shakhmaty- 1926 -Tablas Correction

Solución: 1. Cc7, Ra7; 2. Ab4, d2; 3. Ce3, d1=D; 4. Cd1, c2; 5. Ad2, cxd=D; 6. Ae3, c5; 7. Ac5, Tc5 ahogado –1. Cc3 cook MG, Ta3; 2. Cd1, Ta1; 3. Cge3 =. Si 2…, c5; 3. Cge3, Ta7; 4. Cc4 =.

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Gohn N.- Revista Romana de Sah-1928-Ganan Correction

1.Cb4,Rd6; 2.Dc6,Re7; 3.Cd5,Rf7; 4.Df6,Rg8; 5.Ce7,Rh7; 6.Df7,Rh6; 7.Cf5,Rg5; 8.Dg7,Rf5; 9.Dh7,Rg4; 10.Db1,Ae2; 11.Rb2,d3; 12.Rc3,e4; 13.Dh1,e3; 14.Dg2,Rf4; 15.Dg2,Rf4; 16.Rd4+–En 8…,Rf4!cook HH=

Solución:1.Cb4+! Rd6 2.Dc6+ Re7 3.Cd5+ Rf7 4.Df6+ Rg8 5.Ce7+ Rh7 6.Df7+ Rh6 7.Cf5+ Rg5 8.Dg7+ Rxf5 [8…Rh5 9.Dh7+ Rg5 (9…Rg4 10.Ch6++-) 10.Dh4+ Rg6 11.Dh6+ Rf7 12.Dg7+ Re6 13.Dg6+ Rd7 (13…Rd5 14.Ce7+ Rc4 15.Dxb1+-) 14.Dh7+! Rd8 15.De7+ Rc8 16.Cd6+ Rb8 17.De8+ Rc7 18.Cb5+ Rb6 19.Db8+! Rc5 20.Dxe5+ Rb6 (20…Rc4 21.Dc7+ Rxb5 22.Db7++-) 21.Dc7+ Ra6 22.Da7++-] 9.Dh7+ Rg4 10.Dxb1+-

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Gorgiev T.-Rudenko V.-Ceskoslovensky Sach.-1965.-Tablas Correction

Solución: 1.g3,Rg1; 2.Aa7,Rf1; 3.Ab7,Tc7; 4.Aa6,Re1; 5.Ab6,Tc6; 6.Aa5,Rd1; 7.Ab5,Tc5; 8.Aa4,Rc1; 9.Ab4,Tc4; 10.Aa3,Rb1; 11.Ab3,Tc3; 12.Ag8= En 1.g4cook ,Rg1; 2.Aa7,Rf1; 3.Ae4= ; En 3.Ae4cook=

En consecuencia: 1.Ae4,Rg1; 2.Aa7,Rf1; 3.Ab7 etc ident–

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Guliaiev A. (Grin)- Revista 64- 1935- Ganan Correction

Solución: 1.e7,Cg8; 2.e8=D,Ah5; 3.Rh5,Cf6; 4.Rg6,Ce8; 5.Rf7,b2; 6.Cb2,Cd6; 7.Re6,Cc8; 8.Af1,Rb6; 9.Rd7,Ca7; 10.Ca4+- En 5…,Cd6 cook; 6.Cd6,Rb6; 7.Re6,Rc5; 8.Ae4,a4=

En consecuencia: 1.e7,cxb; 2.Cb2,Cg8; 3.e8=D,Ah5; 4.Rh5, etc. Idem

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