Nº3 Michal Hlinka & Ľuboš Kekely

Win

Section B.1.

Michal Hlinka & Ľuboš Kekely (Slovakia)

wKh3,Nd1,Rh5,h6,Pd4,g7/bKe8,Qf4,Rg6,Pf7

1.Re5+!
1.Rxg6? Qf3+! 2.Kh4 Qh1+ 3.Kg5 Qg1+ 4.Kh4 Qh2+ 5.Kg4 Qg1+ 6.Kf4 Qxd4+=

1…Qxe5!
1…Kd7 2.Rxg6+-

2.Rh8+
2.dxe5? Rxh6+=

a) 2…Ke7 3.dxe5 Rxg7 4.Ne3!
try 4.Nf2? f6=

4…Rg1
4…Ke6 5.Re8+ Kd7 6.Ra8 Ke6 7.Ng4 Kf5 8.Ra4 Rg6 9.Kg3+-

5.Nf5+ Ke6 6.Nd4+ Kd5
6…Kxe5 7.Nf3++- fork

7.Rd8+ Ke4 8.Nc6 Rg6
8…Rc1 9.Rd6

9.Rd6 and wins
(9.Rd4+? Kf5 10.Rd6 (10.Rc4 Rh6+ 11.Kg3 f6=) 10…Rxd6 11.exd6 Ke6=),

b) 2…Kd7 3.dxe5 Rxg7 4.Nf2!
try 4.Ne3? Rg1! 5.Ng4 Rh1+ 6.Nh2 Re1 7.Rh5 Ke6 8.Nf3 Rh1+ 9.Kg4 Rxh5 10.Kxh5 f6=

4…Ke6
4…Rg1 5.Rh6+-

5.Ng4
5.Nd3? f6=
5.Re8+? Kf5 6.Nd3 Ke4 7.Nc5+ Kf4 8.Re7 Rg3+ 9.Kh2 Rg5 10.Nd7 Kf5 11.Rxf7+ Ke6 12.Rh7 Rg4 13.Kh3 Rd4=

5…Kf5 6.Rh5+!
try 6.Rh4? Kf4! Zz

6…Kf4 7.Rh4! zz 7…Rg6
7…Kf5 8.Kg3+-
7…Kf3 8.Nh2++-

8.Rh7 Rxg4 9.Rxf7+ and wins, for example 9…Kg5 10.Rg7+ Kf5 11.Rxg4

Change of tries and solutions among main a) and b). Reciprocal zugzwang