Diag.12 Mikhael Croitor-Moldova
3/4.hm Neidze JT, 2007-Tablas
wKe4,Bc1,Rb6,Pa7/bKe8,Ng6,Bf7,Ra8,Pb7
Solución:
1.Txb7 Ad5+ 2.Rxd5 0–0–0+ 3.Rc6 Ce5+ 4.Rb6 Cc4+ [4…Td6+ 5.Rc5 Tc6+ 6.Rd5 Rxb7 7.a8D+ Rxa8 8.Af4] 5.Rc6 Td6+ 6.Rc5 Rxb7 7.a8D+ Rxa8 8.Ab2 Td2 9.Ac3 =